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View Full Version : Math geniuses... in here, now!


IEatFriedPikmin
04-25-2005, 12:11 AM
I am doing integration of partial functions in calculus, and I was busy thinking about nothing during class when we took notes.... now I can either figure it out on my own by reading the book, or someone could give me... or sorry... help me with the answers.

here is the first one.

Find the integral of ((5x-12)/(x(x-4))) dx

Remember you have to use the rules that apply to integration of partial functions. If anyone can do this, you get a rep point.... but I really doubt anyone can.

WOW! I"M HIGH
04-25-2005, 12:26 AM
pay attention in school next time..I hope you fail.

dork
04-25-2005, 01:28 AM
I dunno the answer :(

Crun
04-25-2005, 12:44 PM
Nodding off is fine in english class, but you'd better start paying attention in calc class. Wait till they spin hyperbolas around the x-axis and ask you for the volume of the resulting solid.

Nate
04-25-2005, 01:00 PM
((5x-12)/(x(x-4))) dx

I dont see why we have to learn this kind of shit in school. I plan to be a musician....not an astronaut.

Kay B
04-25-2005, 01:06 PM
how can any numbers times/divided/plussed ect equal letter ffs...........

WolfmanNCSU
04-25-2005, 06:56 PM
Hmmm, looking back at this now shows me that I have forgot how to do calculus. Amazing because I took 3 semesters of it in college and could do it in multiple (infinite) dimensions. Its just been so long now since I had to touch it.

Viper
04-25-2005, 07:05 PM
^I'm having a similar problem except I took 1 year of it in high school....10 years ago.


Ok, you add 4 to both sides and then 12 to both sides. Then divide by X...um..twice and it all equals D for Don't ask.

Peter
04-25-2005, 10:42 PM
I don;t really understand your topic, since the US usues completely different Maths and features more calculus. But, if you mean to just integrate the damn thing, heres what I got, if the value gave me is f'(x) (differentiated).

(Please note it may not be right, my indicie powers and algebraic skills are not thatsuperior...)

1. I split it into different diisions.

(5x/x^2-4x) - (12/x^2-4x)

My answer;


5/4x^-2 - 12x^-2 - 3x.

Simplified;

-10 3/4 - 3x = 43/4x^-2 - 3x

Integrated;

(43/4x^-1)/-1 - (3x^2)/2

=

-43/4x^-1 - 3/2x^2

I think its more than just plain integration, but thats what I got. Was kinda fun actually just now. we use integration to find area underneath the curve and such.

Calculus is different dimensions is a piece of piss, just integrate or differentiate again.

Gilly
04-25-2005, 11:51 PM
I'm not so sure that I wanna take Calc next year now...

Oh well, I love a challenge.